4[x+(2-3x)]=2(4+4x)

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Solution for 4[x+(2-3x)]=2(4+4x) equation:


Simplifying
4[x + (2 + -3x)] = 2(4 + 4x)

Remove parenthesis around (2 + -3x)
4[x + 2 + -3x] = 2(4 + 4x)

Reorder the terms:
4[2 + x + -3x] = 2(4 + 4x)

Combine like terms: x + -3x = -2x
4[2 + -2x] = 2(4 + 4x)
[2 * 4 + -2x * 4] = 2(4 + 4x)
[8 + -8x] = 2(4 + 4x)
8 + -8x = (4 * 2 + 4x * 2)
8 + -8x = (8 + 8x)

Add '-8' to each side of the equation.
8 + -8 + -8x = 8 + -8 + 8x

Combine like terms: 8 + -8 = 0
0 + -8x = 8 + -8 + 8x
-8x = 8 + -8 + 8x

Combine like terms: 8 + -8 = 0
-8x = 0 + 8x
-8x = 8x

Solving
-8x = 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
-8x + -8x = 8x + -8x

Combine like terms: -8x + -8x = -16x
-16x = 8x + -8x

Combine like terms: 8x + -8x = 0
-16x = 0

Divide each side by '-16'.
x = 0

Simplifying
x = 0

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